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2x^2+360x-129600=0
a = 2; b = 360; c = -129600;
Δ = b2-4ac
Δ = 3602-4·2·(-129600)
Δ = 1166400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1166400}=1080$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-1080}{2*2}=\frac{-1440}{4} =-360 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+1080}{2*2}=\frac{720}{4} =180 $
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